SmileBASIC コミュニティ返信[8]親投稿Hanzo rzsense2017/6/4 8:59Use Autz's method, but return value of CHKCHR is integer type (not string type). To check presence of letter or character at X,Y on console screen, do as follows. IF CHKCHR(X,Y)==ASC("(letter or character)") THEN ... 1そうだね 未プレイ2017/11/04 02:07:18に取得