SmileBASIC コミュニティプレイ日記ιм оιd мαп spinoff232017/08/12 14:23:24This doesn't make sense.1そうだね 8返信プレイ済み2017/11/04 01:53:41に取得
SmileBASIC コミュニティ返信[1]親投稿ιм оιd мαп spinoff232017/8/13 1:21Can anyone explain to me how this works0そうだね プレイ済み2017/11/04 01:53:41に取得
SmileBASIC コミュニティ返信[2]親投稿*J.P.* DEV NEWPICY32017/8/13 4:45take a look at my raycast basic tutorial. it does make sense but is easyer to just test with.0そうだね プレイ済み2017/11/04 01:53:41に取得
SmileBASIC コミュニティ返信[4]親投稿ιм оιd мαп spinoff232017/8/13 10:53I don't understand what it's trying to tell me.1そうだね プレイ済み2017/11/04 01:53:41に取得
SmileBASIC コミュニティ返信[5]親投稿ιм оιd мαп spinoff232017/8/13 14:13I can understand it now0そうだね プレイ済み2017/11/04 01:53:41に取得
SmileBASIC コミュニティ返信[6]親投稿ιм оιd мαп spinoff232017/8/13 14:33How would I make it so if I click the right button while the cursor is on the block, it recreates it?0そうだね プレイ済み2017/11/04 01:53:41に取得
SmileBASIC コミュニティ返信[7]親投稿ιм оιd мαп spinoff232017/8/13 16:09Or like when I break the block, it has a timer to respawn.0そうだね プレイ済み2017/11/04 01:53:41に取得
SmileBASIC コミュニティ返信[8]親投稿*J.P.* DEV NEWPICY32017/8/13 16:42*not tested* but i think maybe by doing the opposite and if its the 0 block then BLOCK[CX,CY]=1 (uh if thats what its called, i havent used raycasting in a while..) i might test this though.0そうだね プレイ済み2017/11/04 01:53:41に取得
